On the interpretation of the OUTCAR file from LDA+U with LDAUPRINT=1
Moderators: Global Moderator, Moderator
On the interpretation of the OUTCAR file from LDA+U with LDAUPRINT=1
Dear all,
I have a compound with d atomic oribitals.
I did the calculation with LDAUL=2 for that atom.
The output of the occupancies for the d orbitals
is printed out as follows.
Could anyone kind give an detailed explanation
on the format of the output and simple physical interpretations for those quantities?
The coefficients of the eigenvector of d orbitals seems to depend on
the orientation of the local coordinate of the atom.
What are the corresponding coefficients in the d orbitals?
It's always confusing to me that how VASP determine
the orientation of the local coordinates because the value of
the coefficients really depend on it.
Sincerely
atom = 6 type = 3 l = 2
onsite density matrix
spin component 1
0.1428 0.0173 0.0059 0.0004 -0.0278
0.0173 0.0642 -0.0032 -0.0068 -0.0083
0.0059 -0.0032 0.1449 -0.0346 -0.0066
0.0004 -0.0068 -0.0346 0.0816 -0.0027
-0.0278 -0.0083 -0.0066 -0.0027 0.0715
spin component 2
0.1537 0.0269 0.0087 0.0021 -0.0281
0.0269 0.5097 0.0625 0.0962 0.3061
0.0087 0.0625 0.1661 -0.0238 0.0405
0.0021 0.0962 -0.0238 0.1077 0.0695
-0.0281 0.3061 0.0405 0.0695 0.2945
occupancies and eigenvectors
o = 0.0526 v = 0.0160 -0.7030 -0.2444 -0.4990 -0.4436 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.0613 v = 0.0000 0.0000 0.0000 0.0000 0.0000 0.3854 -0.5026 -0.0574 -0.1419 0.7586 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.0633 v = 0.3803 -0.4462 -0.0098 -0.0717 0.8069 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.0704 v = 0.0000 0.0000 0.0000 0.0000 0.0000 -0.0251 0.2579 -0.3822 -0.8870 -0.0112 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.0725 v = -0.0097 0.5158 -0.3209 -0.7637 0.2181 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.1516 v = 0.7475 0.1700 -0.5347 0.2610 -0.2415 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.1638 v = 0.0000 0.0000 0.0000 0.0000 0.0000 0.7239 0.1798 -0.5574 0.2750 -0.2394 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.1650 v = -0.5444 -0.1081 -0.7425 0.3073 0.2150 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.1795 v = 0.0000 0.0000 0.0000 0.0000 0.0000 0.5715 0.1062 0.7256 -0.2951 -0.2203 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.7567 v = 0.0000 0.0000 0.0000 0.0000 0.0000 -0.0116 -0.7983 -0.1163 -0.1745 -0.5644 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
I have a compound with d atomic oribitals.
I did the calculation with LDAUL=2 for that atom.
The output of the occupancies for the d orbitals
is printed out as follows.
Could anyone kind give an detailed explanation
on the format of the output and simple physical interpretations for those quantities?
The coefficients of the eigenvector of d orbitals seems to depend on
the orientation of the local coordinate of the atom.
What are the corresponding coefficients in the d orbitals?
It's always confusing to me that how VASP determine
the orientation of the local coordinates because the value of
the coefficients really depend on it.
Sincerely
atom = 6 type = 3 l = 2
onsite density matrix
spin component 1
0.1428 0.0173 0.0059 0.0004 -0.0278
0.0173 0.0642 -0.0032 -0.0068 -0.0083
0.0059 -0.0032 0.1449 -0.0346 -0.0066
0.0004 -0.0068 -0.0346 0.0816 -0.0027
-0.0278 -0.0083 -0.0066 -0.0027 0.0715
spin component 2
0.1537 0.0269 0.0087 0.0021 -0.0281
0.0269 0.5097 0.0625 0.0962 0.3061
0.0087 0.0625 0.1661 -0.0238 0.0405
0.0021 0.0962 -0.0238 0.1077 0.0695
-0.0281 0.3061 0.0405 0.0695 0.2945
occupancies and eigenvectors
o = 0.0526 v = 0.0160 -0.7030 -0.2444 -0.4990 -0.4436 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.0613 v = 0.0000 0.0000 0.0000 0.0000 0.0000 0.3854 -0.5026 -0.0574 -0.1419 0.7586 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.0633 v = 0.3803 -0.4462 -0.0098 -0.0717 0.8069 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.0704 v = 0.0000 0.0000 0.0000 0.0000 0.0000 -0.0251 0.2579 -0.3822 -0.8870 -0.0112 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.0725 v = -0.0097 0.5158 -0.3209 -0.7637 0.2181 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.1516 v = 0.7475 0.1700 -0.5347 0.2610 -0.2415 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.1638 v = 0.0000 0.0000 0.0000 0.0000 0.0000 0.7239 0.1798 -0.5574 0.2750 -0.2394 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.1650 v = -0.5444 -0.1081 -0.7425 0.3073 0.2150 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.1795 v = 0.0000 0.0000 0.0000 0.0000 0.0000 0.5715 0.1062 0.7256 -0.2951 -0.2203 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
o = 0.7567 v = 0.0000 0.0000 0.0000 0.0000 0.0000 -0.0116 -0.7983 -0.1163 -0.1745 -0.5644 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
Last edited by joseph on Sat May 19, 2007 3:00 am, edited 1 time in total.
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- Global Moderator
- Posts: 1817
- Joined: Mon Nov 18, 2019 11:00 am
Re: On the interpretation of the OUTCAR file from LDA+U with LDAUPRINT=1
Hi,
We're sorry that we didn’t answer your question. This does not live up to the quality of support that we aim to provide. The team has since expanded. If we can still help with your problem, please ask again in a new post, linking to this one, and we will answer as quickly as possible.
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VASP