Number of electrons for PARCHG for each k and n is 2?
Posted: Mon Oct 16, 2023 4:33 pm
Dear All,
I am afraid that the number of electrons for each quantum number, i.e., crystal momentum k and band-index n, is always 2 in my atomic chain calculation. It is different from the results of solid state text book. The detail information is as follows,
I want to calculate the PARCHG of each quantum number k and n for one-dimensional Aluminum atomic chain. My POSCAR, INCAR and KPOINTS are as follows,
POSCAR 2.50
1.0000
10.000 0.0000 0.0000
0.0000 10.0000 0.0000
0.0000 0.0000 2.419079874528345
Al
1
Direct
0.5000 0.5000 0.5000
INCAR
RWIGS = 1.402
ENCUT = 241
IALGO = 48
EDIFF = 1E-05
NELM = 999
ISMEAR = 0
SIGMA = 0.05
ISIF = 2
IBRION = -1
NSW = 0
LCHARG = .TRUE.
ISYM = -1
KPOINTS file
0
M
1 1 100
0 0 0
The PAW_PBE Al 04Jan2001 POTCAR was used. Furthermore, the unconventional settings, i.e., ISYM = -1 and 100 k-points are for some purposes. After the scf calculation was finished, I created another directory named PARCHG_1 and copied the POSCAR, KPOINTS, POTCAR and WAVECAR to the directory PARCHG_1. The INCAR was also modified to calculate the partial charge. The new INCAR is as follows,
RWIGS = 1.402
ENCUT = 241
IALGO = 48
EDIFF = 1E-05
NELM = 999
ISMEAR = 0
SIGMA = 0.05
ISIF = 2
IBRION = -1
NSW = 0
ISYM = -1
LPARD = .TRUE.
IBAND = 1
KPUSE = 1 2
LSEPK = .TRUE.
LSEPB = .TRUE.
After the calculations, there are two PARCHG files, i.e., PARCHG.0001.0001 and PARCHG.0001.0002. The number of the real space grids of CHGCAR and PARCHGs are 80*80*20 which was printed after the fractional coordinates in the CHGCAR and PARCHGs. The total number of electrons can be calculated by adding all the raw values of charge density in CHGCAR then dividing by the number of the real space grids (80*80*20). The result is 3.0000000341180426 which is consistent with the number of the valence electrons of Aluminum of the POTCAR. However, when the I did the same procedure for the PARCHG.0001.0001 (n = 1, k = 1) and PARCHG.0001.0002 (n = 1, k = 2); adding all raw charge density values in the PARCHG then divide the values by 80*80*20. The number of electrons are 2.00000091 and 1.99999981 for PARCHG.0001.0001 and PARCHG.0001.0002, respectively. According to the solid state physics, for the spin degenerate case, there are 2 electrons for each band for one-dimensional system, it means that for each band, summation for all k-points (ISYM = -1) will get 2. I did not expect that there are 2 electrons for each quantum number k and n. Would you please let me know which part is incorrect? Thank you very much in advanced.
I am afraid that the number of electrons for each quantum number, i.e., crystal momentum k and band-index n, is always 2 in my atomic chain calculation. It is different from the results of solid state text book. The detail information is as follows,
I want to calculate the PARCHG of each quantum number k and n for one-dimensional Aluminum atomic chain. My POSCAR, INCAR and KPOINTS are as follows,
POSCAR 2.50
1.0000
10.000 0.0000 0.0000
0.0000 10.0000 0.0000
0.0000 0.0000 2.419079874528345
Al
1
Direct
0.5000 0.5000 0.5000
INCAR
RWIGS = 1.402
ENCUT = 241
IALGO = 48
EDIFF = 1E-05
NELM = 999
ISMEAR = 0
SIGMA = 0.05
ISIF = 2
IBRION = -1
NSW = 0
LCHARG = .TRUE.
ISYM = -1
KPOINTS file
0
M
1 1 100
0 0 0
The PAW_PBE Al 04Jan2001 POTCAR was used. Furthermore, the unconventional settings, i.e., ISYM = -1 and 100 k-points are for some purposes. After the scf calculation was finished, I created another directory named PARCHG_1 and copied the POSCAR, KPOINTS, POTCAR and WAVECAR to the directory PARCHG_1. The INCAR was also modified to calculate the partial charge. The new INCAR is as follows,
RWIGS = 1.402
ENCUT = 241
IALGO = 48
EDIFF = 1E-05
NELM = 999
ISMEAR = 0
SIGMA = 0.05
ISIF = 2
IBRION = -1
NSW = 0
ISYM = -1
LPARD = .TRUE.
IBAND = 1
KPUSE = 1 2
LSEPK = .TRUE.
LSEPB = .TRUE.
After the calculations, there are two PARCHG files, i.e., PARCHG.0001.0001 and PARCHG.0001.0002. The number of the real space grids of CHGCAR and PARCHGs are 80*80*20 which was printed after the fractional coordinates in the CHGCAR and PARCHGs. The total number of electrons can be calculated by adding all the raw values of charge density in CHGCAR then dividing by the number of the real space grids (80*80*20). The result is 3.0000000341180426 which is consistent with the number of the valence electrons of Aluminum of the POTCAR. However, when the I did the same procedure for the PARCHG.0001.0001 (n = 1, k = 1) and PARCHG.0001.0002 (n = 1, k = 2); adding all raw charge density values in the PARCHG then divide the values by 80*80*20. The number of electrons are 2.00000091 and 1.99999981 for PARCHG.0001.0001 and PARCHG.0001.0002, respectively. According to the solid state physics, for the spin degenerate case, there are 2 electrons for each band for one-dimensional system, it means that for each band, summation for all k-points (ISYM = -1) will get 2. I did not expect that there are 2 electrons for each quantum number k and n. Would you please let me know which part is incorrect? Thank you very much in advanced.